New colorful card deck from NYT bestselling spiritual guru, based on her top-selling Spirit Junkie book. 52 energetically charged cards featuring beautiful watercolor illustrations and empowering messages to provide divine guidance, inspiration, and support as you strengthen your spiritual connection. Curated playing cards and magic tricks Shop for all the best brands under one roof Worldwide delivery.

• 52 Card Deck Club
• Deck Of Cards Online
• Cool Card Decks
• 52 Card Deck Games
• 52 Card Deck All Cards In Order
• Card Games 52 Card Deck

Playing cards probability problems based on a well-shuffled deck of 52 cards.

Basic concept on drawing a card:

In a pack or deck of 52 playing cards, they are divided into 4 suits of 13 cards each i.e. spades ♠ hearts ♥, diamonds ♦, clubs ♣.

Cards of Spades and clubs are black cards.

Cards of hearts and diamonds are red cards.

The card in each suit, are ace, king, queen, jack or knaves, 10, 9, 8, 7, 6, 5, 4, 3 and 2.

King, Queen and Jack (or Knaves) are face cards. So, there are 12 face cards in the deck of 52 playing cards.

Worked-out problems on Playing cards probability:

1. A card is drawn from a well shuffled pack of 52 cards. Find theprobability of:

(i) ‘2’ of spades

(ii) a jack

(iii) a king of red colour

(iv) a card of diamond

(v) a king or a queen

(vi) a non-face card

(vii) a black face card

(viii) a black card

(ix) a non-ace

(x) non-face card of black colour

(xi) neither a spade nor a jack

(xii) neither a heart nor a red king

Solution:

In a playing card there are 52 cards.

Therefore the total number of possibleoutcomes = 52

(i) ‘2’ of spades:

Number of favourable outcomes i.e. ‘2’ ofspades is 1 out of 52 cards.

Therefore, probability of getting ‘2’ ofspade

Number of favorable outcomes
^{P(A) =} Total number of possible outcome
= 1/52

(ii) a jack

Number of favourable outcomes i.e. ‘a jack’is 4 out of 52 cards.

Therefore, probability of getting ‘a jack’

Number of favorable outcomes
^{P(B) =} Total number of possible outcome
= 4/52
= 1/13

(iii) a king of red colour

Number of favourable outcomes i.e. ‘a kingof red colour’ is 2 out of 52 cards.

Therefore, probability of getting ‘a kingof red colour’

Number of favorable outcomes
^{P(C) =} Total number of possible outcome
= 2/52
= 1/26

(iv) a card of diamond

Number of favourable outcomes i.e. ‘a cardof diamond’ is 13 out of 52 cards.

Therefore, probability of getting ‘a cardof diamond’

Number of favorable outcomes
^{P(D) =} Total number of possible outcome
= 13/52
= 1/4

(v) a king or a queen

Total number of king is 4 out of 52 cards.

Total number of queen is 4 out of 52 cards

Number of favourable outcomes i.e. ‘a kingor a queen’ is 4 + 4 = 8 out of 52 cards.

Therefore, probability of getting ‘a kingor a queen’

Number of favorable outcomes
^{P(E) =} Total number of possible outcome
= 8/52
= 2/13

(vi) a non-face card

Total number of face card out of 52 cards =3 times 4 = 12

Total number of non-face card out of 52cards = 52 - 12 = 40

Therefore, probability of getting ‘anon-face card’

Number of favorable outcomes
^{P(F) =} Total number of possible outcome
= 40/52

52 Card Deck Club

= 10/13

(vii) a black face card:

Cardsof Spades and Clubs are black cards.

Number of face card in spades (king, queenand jack or knaves) = 3

Number of face card in clubs (king, queen andjack or knaves) = 3

Therefore, total number of black face cardout of 52 cards = 3 + 3 = 6

Therefore, probability of getting ‘a blackface card’

Number of favorable outcomes
^{P(G) =} Total number of possible outcome
= 6/52
= 3/26

(viii) a black card:

Cards of spades and clubs are black cards.

Number of spades = 13

Number of clubs = 13

Therefore, total number of black card outof 52 cards = 13 + 13 = 26

Therefore, probability of getting ‘a blackcard’

Number of favorable outcomes
^{P(H) =} Total number of possible outcome
= 26/52
= 1/2

(ix) a non-ace:

Number of ace cards in each of four suits namelyspades, hearts, diamonds and clubs = 1

Therefore, total number of ace cards out of52 cards = 4

Thus, total number of non-ace cards out of52 cards = 52 - 4

= 48

Therefore, probability of getting ‘anon-ace’

Number of favorable outcomes
^{P(I) =} Total number of possible outcome
= 48/52
= 12/13

(x) non-face card of black colour:

Cards of spades and clubs are black cards.

Number of spades = 13

Number of clubs = 13

Therefore, total number of black card outof 52 cards = 13 + 13 = 26

Number of face cards in each suits namelyspades and clubs = 3 + 3 = 6

Therefore, total number of non-face card ofblack colour out of 52 cards = 26 - 6 = 20

Therefore, probability of getting ‘non-facecard of black colour’

Number of favorable outcomes
^{P(J) =} Total number of possible outcome
= 20/52
= 5/13

(xi) neither a spade nor a jack

Number of spades = 13

Total number of non-spades out of 52 cards= 52 - 13 = 39

Number of jack out of 52 cards = 4

Number of jack in each of three suitsnamely hearts,diamonds and clubs = 3

[Since, 1 jack is already included in the13 spades so, here we will take number of jacks is 3]

Neither a spade nor a jack = 39 - 3 = 36

Therefore, probability of getting ‘neithera spade nor a jack’

Number of favorable outcomes
^{P(K) =} Total number of possible outcome
= 36/52
= 9/13

(xii) neither a heart nor a red king

Number of hearts = 13

Total number of non-hearts out of 52 cards= 52 - 13 = 39

Therefore, spades, clubs and diamonds arethe 39 cards.

Cardsof hearts and diamonds are red cards.

Number of red kings in red cards = 2

Therefore, neither a heart nor a red king =39 - 1 = 38

[Since, 1 red king is already included inthe 13 hearts so, here we will take number of red kings is 1]

Therefore, probability of getting ‘neithera heart nor a red king’

Number of favorable outcomes
^{P(L) =} Total number of possible outcome
= 38/52
= 19/26

2. A card is drawn at random from a well-shuffled pack of cards numbered 1 to 20. Find the probability of

(i) getting a number less than 7

(ii) getting a number divisible by 3.

Solution:

(i) Total number of possible outcomes = 20 ( since there are cards numbered 1, 2, 3, ..., 20).

Number of favourable outcomes for the event E

= number of cards showing less than 7 = 6 (namely 1, 2, 3, 4, 5, 6).

So, P(E) = (frac{textrm{Number of Favourable Outcomes for the Event E}}{textrm{Total Number of Possible Outcomes}})

= (frac{6}{20})

= (frac{3}{10}).

Deck Of Cards Online

(ii) Total number of possible outcomes = 20.

Number of favourable outcomes for the event F

= number of cards showing a number divisible by 3 = 6 (namely 3, 6, 9, 12, 15, 18).

So, P(F) = (frac{textrm{Number of Favourable Outcomes for the Event F}}{textrm{Total Number of Possible Outcomes}})

= (frac{6}{20})

= (frac{3}{10}).

3. A card is drawn at random from a pack of 52 playing cards. Find the probability that the card drawn is

(i) a king

(ii) neither a queen nor a jack.

Solution:

Total number of possible outcomes = 52 (As there are 52 different cards).

(i) Number of favourable outcomes for the event E = number of kings in the pack = 4.

So, by definition, P(E) = (frac{4}{52})

= (frac{1}{13}).

(ii) Number of favourable outcomes for the event F

= number of cards which are neither a queen nor a jack

= 52 - 4 - 4, [Since there are 4 queens and 4 jacks].

= 44

Cool Card Decks

Therefore, by definition, P(F) = (frac{44}{52})

= (frac{11}{13}).

These are the basic problems on probability with playingcards.

You might like these

• Theoretical Probability |Classical or A Priori Probability |Definition

  Moving forward to the theoretical probability which is also known as classical probability or priori probability we will first discuss about collecting all possible outcomes and equally likely outcome. When an experiment is done at random we can collect all possible outcomes

• 10th Grade Worksheet on Probability |Probability Questions and Answers

  In 10th grade worksheet on probability we will practice various types of problems based on definition of probability and the theoretical probability or classical probability. 1. Write down the total number of possible outcomes when the ball is drawn from a bag containing 5

• Probability |Terms Related to Probability|Tossing a Coin|Coin Probabil

  Probability in everyday life, we come across statements such as: Most probably it will rain today. Chances are high that the prices of petrol will go up. I doubt that he will win the race. The words ‘most probably’, ‘chances’, ‘doubt’ etc., show the probability of occurrence

• Worksheet on Playing Cards | Playing Cards Probability | With Answers

  In math worksheet on playing cards we will solve various types of practice probability questions to find the probability when a card is drawn from a pack of 52 cards. 1. Write down the total number of possible outcomes when a card is drawn from a pack of 52 cards.

• Rolling Dice Probability Worksheet |Dice Probability Worksheet|Answers

  Practice different types of rolling dice probability questions like probability of rolling a die, probability for rolling two dice simultaneously and probability for rolling three dice simultaneously in rolling dice probability worksheet. 1. A die is thrown 350 times and the

Probability

Events in Probability

Probability for Rolling Two Dice

52 Card Deck Games

9th Grade Math

52 Card Deck All Cards In Order

Card Games 52 Card Deck

Didn't find what you were looking for? Or want to know more informationaboutMath Only Math.Use this Google Search to find what you need.